Question

A committee of 5 is to be formed out of a group of 7 men and 6 women. Find the probability that in the committee there will be 3 men and 2 women​

Answer 1

Answer:

Case 1: 3 Men, 2 Women

⇒

7

C

3

×

6

C

2

=35×15=525

Case 2: 4 Men, 1 Women

⇒

7

C

4

×

6

C

1

=35×6=210

Case 3: 5 Men, 0 Women

⇒

7

C

5

=21

⇒ Total =525+210+21

=756

Hence, the answer is 756.

Answer 2

Answer:

Did you understand???

Step-by-step explanation:

Thus, the number of ways to select 3 men and 2 women is 35 x 15 = 525. Thus, the number of ways to select 4 men and 1 woman is 35 x 6 = 210. azamaka wrote: From a group of 7 men and 6 women, five persons are to be selected to form a committee so that at least 3 men are there on the committee.