Math, asked by mahakjain20, 1 year ago

A committee of 5 member is to be formed out of 3 trainees, 4professors and 6 research associate in how many different ways can this be done if the committee should have 4 professor and 1 research associate or all 3 trainees and 2 professors?

Answers

Answered by KartikSharma13
16
Five members team with 4 professors and 1 research associate can be selected in

= 4C4×6C1=1×6=6ways4C4×6C1=1×6=6ways

Vive members team with 3 trainees and 2 professors can be selected

in = 3C2×4C2=1×6=6ways3C2×4C2=1×6=6ways

Total number of required ways = 6 + 6 = 12
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