Question

A committee of 5 people is to be chosen from a group of 12 people 6 women and 6 men. In how many ways can the committee be chosen so as to include exactly 3 men​

Answer 1

Such a committee can have 2 men+2 women, 3 men+1 women or 4 men+0 women. The number of ways of achieving these outcomes are:

Ways for 2 men+2 women combinations = [6!/(4!)(2!)]*[5!/(3!)(2!)] = 150.

Ways for 3 men+1 women combinations = [6!/(3!)(3!)]*[5!/(4!)(1!)] = 100.

Ways for 4 men+0 women combinations = [6!/(2!)(4!)]*[5!/(5!)(0)] = 15.

Total of ways as requested = 150+100+15 = 265.

Follow me and mark me as brainliest

Answer 2

300/-

$\huge \mathfrak{\fcolorbox{orange}{orange}{ \fcolorbox{yellow}{yellow}{ \fcolorbox{blue}{blue}{solution}}}}$

In Image