Math, asked by vjdonvijesh1, 2 days ago

A committee of 5 people is to be chosen froma group of 6 men and 4 women.
How many committees are possible if:
a) there are to be 3 men and 2 women?
b) there are to be men only?
c) there is to be a majority of women?​

Answers

Answered by bson
3

total : 6 men and 4 women =10 people

5 to choose from 10 people = 10c5

a) 3 men from 6 men and

2 women from 4 women

6c3×4c2 = 6×5×4/6 * 4×3/2

=6×5×4 = 120

b) 5 men from 6men

6c5 =6c1 =6

c) majority women

i) 4 women 1 man = 4c4×6c1 =6

ii) 3 women 2man = 4c3×6c2

= 4×6×5/2 =60

majority women = 6+60 =66

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