A committee of 6 is chosen from 8 men and 5 women so as to contain at least 2 men and 3 women. how many different committees could be formed if two of the men refuse to serve together?
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hi,
committee can have either: 2 men and 4 women OR 3 men and 3 women (to meet the condition of at least 2 men and 3 women).
Ways to chose 6 members committee without restriction (two men refuse to server together): \(C^2_8*C^4_5+C^3_8*C^3_5 = 700\)
Ways to chose 6 members committee with two particular men serve together: \(C^2_2*C^4_5+(C^2_2*C^1_6)*C^3_5=5+60=65\)
700-65 = 635
HOPE U GET IT
MARK AS AN BRAINLIEST ANS
committee can have either: 2 men and 4 women OR 3 men and 3 women (to meet the condition of at least 2 men and 3 women).
Ways to chose 6 members committee without restriction (two men refuse to server together): \(C^2_8*C^4_5+C^3_8*C^3_5 = 700\)
Ways to chose 6 members committee with two particular men serve together: \(C^2_2*C^4_5+(C^2_2*C^1_6)*C^3_5=5+60=65\)
700-65 = 635
HOPE U GET IT
MARK AS AN BRAINLIEST ANS
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