A committee of five will be chosen from 3 referees, 4 umpires and 6 scorers. What is the probability that there will be at least 3 scorers in the committee?
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Answer :
- 5 member committee make out of
- 3 referees+ 4 umpires+ 6 scorers = 13 member
# total selection = 13c5 = 1287
at least 3 scorer (x = 3,4,5) valid
case 1 = 3 scorer + 2 (referee+umpire)
case 2 = 4 scorer + 1 ( referee / umpire)
caee 3 = all 5 scorer
= 6c3×7c2 + 6c2×7c1 + 6c5
= 420 + 105 + 6
= 531
Answer = 531/1287
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