Math, asked by varz3418, 15 hours ago

A committee of five will be chosen from 3 referees, 4 umpires and 6 scorers. What is the probability that there will be at least 3 scorers in the committee?

Answers

Answered by arjun6355m
1

Answer :

  • 5 member committee make out of
  • 3 referees+ 4 umpires+ 6 scorers = 13 member

# total selection = 13c5 = 1287

at least 3 scorer (x = 3,4,5) valid

case 1 = 3 scorer + 2 (referee+umpire)

case 2 = 4 scorer + 1 ( referee / umpire)

caee 3 = all 5 scorer

= 6c3×7c2 + 6c2×7c1 + 6c5

= 420 + 105 + 6

= 531

Answer = 531/1287

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