Question

A communication satellite launched at 42000 km abc Earth. Find its orbital speed.
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Answer 1

Answer:

2876ms-1

Explanation:

h = 42000km

h=4.2×10^7 m

G=6.673×10^-11 Nm^2 Kg^-2

Me=6×10^24 Kg

R=6.4×10^6 m

v=

$\sqrt{gh(r + h)}$

we know that

gh = GMe/ (r+h)^2

so V= GMe/ (R+h)

put the value and solve it

answer = 2876ms-1