Question

A commuter train travel from station 1 and station 2 and back in 1 hour and 35 minutes
the distance between the two station is approximate 20 miles.
(A) What is the average velocity of the train?
(B) What is the average speed of the train in m/s?​

Answer 1

Answer:

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Explanation:

A). Average velocity of the object is the net displacement of the object per unit time. As the train travels from A to B and then back to the same point/station. The net displacement of the train is zero. Therefore the average velocity of the train is also zero.

B). Starting with km/h,

First work out the distance covered in 1 minute.

42 / 80 = 0.525 km

This is the distance travelled in 1 minute, 0.525 km.

Then multiply that by 60 (the amount of minutes in an hour), to obtain the distance travelled in one hour.

0.525 * 60 = 31.5 km/h

Now for the m/s,

We can start by turning km/h into m/h. There are 1000 metres in a km.

Hence we multiply by 1000.

31.5 * 1000 = 31500 m/h

Now we need to turn m/h into m/s, we know there are 60 minutes in an hour and 60 seconds in a minute, hence there are 60 * 60 seconds in an hour, 3600.

To get m/s we divide by 3600.

31500 / 3600 = 8.75 m/s

So, 31.5 km/h and 8.75 m/s.