A compact subset of a Housedorff
space is
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Answered by
1
Answer:
Each compact subset of a Hausdorff space is closed. Vyi . Since each Uyi and Vyi are disjoint, we have U and V are disjoint.
Step-by-step explanation:
I hope it helps you.
Answered by
1
Step-by-step explanation:
Theorem 5.5 Each compact subset of a Hausdorff space is closed. Vyi . Since each Uyi and Vyi are disjoint, we have U and V are disjoint.
Hope this helps you
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