Math, asked by khushi892345, 7 hours ago

A company can repair 2whole1/5 km of road in a day. How many days will it take to repair a road 24 whole 3/5km long.

Answers

Answered by KaoJ
0

Answer:

Length of road that can be fixed in 1 day = 2 \frac{1}{5}  \: km =  \frac{11}{5}  \: km

Length of road that can be fixed in 'x' days = 24 \frac{3}{5} \:  km =  \frac{123}{5}  \: km

No. of days (Value of 'x')

 =  \frac{123}{5}  \div  \frac{11}{5}  \\  =  \frac{123}{5}  \times  \frac{5}{11}  \\  =  \frac{123}{11}   \\ = 11 \frac{2}{11}  \: days

Answered by stark1997gamer
0

Answer:

11+2/11 days

Explanation:

given : total work = 24+3/5 km

per day work = 2+1/5 km

therefore no of days = (24+ 3/5)km ÷ (2+1/5)km/day

= (24×5)+3 ÷ (2×5)+1

5 5

= 123 (since 5 got cancelled by each other)

11

= 11+2/11 days

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