Question

A company could advertise about its new product in 4 magazines, 3 newspapers and 2 television channels. But in a later move it decided to give advertisements in only 2 of the magazines, one of the newspapers and one the TV channels. In how many ways can

Answer 1

Answer:

36

Step-by-step explanation:

choosing 2 magazines out of 4 magazines in 4C2 ways =        6 ways

and(x) choosing 1 newspaper out of 3 newspaper in 3C1 ways =  3 ways

and(x) choosing 1 T.V out of 2 T.V  in 2C1 ways                          =   2 ways

                                                                                          -------------------------

                                                                                      total : 36 ways

Answer 2

Permutation and Combination

Given:

Number of magazines is 4.

Number of newspaper is 3.

Number of television channels is 2.

After final decision, 2 magazines, 1 newspapers, 1 TV channels are used.

To find:

Number of ways in which it can be done.

Explanation:

Number of ways will be the product of (ways of choosing 2 magazines from 4 magazines) , (ways of choosing 1 newspaper from 3 newspaper) and (ways of choosing 1 TV channels from 2 channels).

Number of ways of  choosing 2 magazines from 4 magazines$={4 \choose 2}=\frac{4!}{2!\times2!} =6$

Number of ways of choosing 1 newspaper from 3 newspaper

$={3 \choose 1}=\frac{3!}{2!\times1!} =3$

Number of ways of choosing 1 TV channels from 2 channels

$={2 \choose 1}=\frac{2!}{1!\times1!} =2$

Total number of ways of choosing will be

$(6\times\ 3\times 2)=36$ ways.

Hence, total 36 ways are there.