Math, asked by Abhishrk6687, 1 year ago

A company has 12 machines of equal efficiency in its factory. The annual manufacturing expenses are Rs. 24, 000 and the establishment charges are Rs. 10, 000. The annual output of the company is Rs. 48, 000. The annual output and manufacturing costs are directly proportional to the no. of machines while the share holders get the 10% profit, which is directly proportional to the annual output of the company. If 8.33% machines remained close throughout the year. Then the percentage decrease in the amount of share holders is :
A.0.1428
B.0.1111
C.0.1666
D.0.0833

Answers

Answered by Anonymous
3
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SOLUTION :-
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Profit, 
= Output - total cost
= 44000 - 32000
= Rs. 12000
Initial value of share holders, 
= 14000 * (10/100) 
= Rs. 1400
New value of share holders, 
= 12000 *(10/100) 
= R

So , Option (A) 0.1428 is the right answer ✔️

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Answered by amitnrw
1

Given : A company has 12 machines of equal efficiency in its factory. The annual manufacturing expenses are Rs. 24, 000 and the establishment charges are Rs. 10, 000. The annual output of the company is Rs. 48, 000. The annual output and manufacturing costs are directly proportional to the no. of machines while the share holders get the 10% profit, which is directly proportional to the annual output of the company.  8.33% machines remained close throughout the year.  

To Find :  the percentage decrease in the amount of share holders is  

A.0.1428

B.0.1111

C.0.1666

D.0.0833

Solution:

Normal condition

Profit = (48000 - 24000  )  - 10000  = 14000

10 % = (10/100)14000 = 1400  Rs

8.33% machines remained close throughout the year.

Hence profit  =  (48000 - 24000  )( 1 - 8.33%)  - 10000

= 22000 - 10000

= 12000

10 % = (10/100)12000 = 1200  Rs

the percentage decrease in the amount of share holders is

= {( 1400 - 1200)/1400 } * 100

= 14.28 %

= 0.1428

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