A company has 5 women and 7 men in management team. CEO of this company want to make a committee of 5 members from management team for special work in new branch. Based on given information, answer the following questions.
(i) Find number of ways if committee has at least one man and one woman.
2 (ii) Find number of ways if committee has at most three man.
Answers
Answered by
0
Answer:
Three men can be chosen from a group of seven in 7C3=35 ways. Each of those 35 can combine with two women, chosen from a group of five, in 5C2=10 ways. So, 350 such groups can be formed.
If two of the men refuse to serve together, we can proceed like so:
Think of the warring pair as a logical unit that can combine with one of the other five men to form a disqualified three-man group: There are five such groupings which we can subtract from our original 35; we now have 30 male trios. So the full calculation is now (7C3–5) * 5C2 = 300.
Step-by-step explanation:
mark
me
as
brainlest
answer
Similar questions