A Company has three plants to manufacture 8,000
scooters in a month. Out of 8,000 scooters, plant I
manufactures 4,000 scooters, Plant II
manufactures 3,000 scooters and the remaining by
Plant III. At plant I, 85 out of 100 scooters are
rated of standard quality or better; at plant II only
65% were rated as standard quality or better and
the plant III 60% was of standard quality or
better. What is the probability that the scooter
selected at random came from
(a) Plant II (b) Plant II and (iii) Plant III, if it is
known, that the scooter is of standard quality or
better.
Answers
Answer:
Step-by-step explanation:
plant 1 is better in quality
Given : A Company has three plants to manufacture 8,000 scooters in a month.
To Find : probability that the scooter selected at random came from
(a) Plant I (b) Plant II and (iii) Plant III, if it is known, that the scooter is of standard quality or better.
Solution:
plant I manufactures 4,000 scooters
85 out of 100 scooters are rated of standard quality or better
=> (85/100)4000 = 3400
plant |I manufactures 3,000 scooters
65% were rated as standard quality or better and
=> (65/100)3000 =1950
plant I|| manufactures 1,000 scooters (8000 - 4000 - 3000)
60% were rated as standard quality or better and
=> (60/100)1000 =600
Scooters of standard Quality = 3400 + 1950 + 600
= 5950
it is known, that the scooter is of standard quality or better.
probability that the scooter selected at random came from
Plant I = 3400/5950 = 0.5714
Plant II = 1950/5950 = 0.3277
Plant III = 600/5950 = 0.1008
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