Question

A company is about to launch a new cell phone model. In the past, 40% of its cell phones have launched successfully. Before any cell phone is launched, the company conducts market research and receives a report predicting favorable or unfavorable sales. In the past, 70% of successful cell phones and 20% of unsuccessful cell phones received favorable reports.​

Answer 1

Answer:

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Answer 2

⚠️ur answere ⚠️

Answer:

Hence, the probability is:

0.70

Step-by-step explanation:

Let x be the total cell phones.

Let A denote the event of cell phone will receive a favorable report.

B denote the event that the cell phone is launched successfully.

Now we have to find the probability:

P(A|B)

We know that P(A|B) is calculated as:

P(A|B)=\dfrac{P(A\bigcap B)}{P(B)}P(A∣B)=

P(B)

P(A⋂B)

Now it is given that:

40% of its cell phones have launched successfully.

i.e. P(B)=0.4xP(B)=0.4x

( Since,

\dfrac{40}{100}\times x=0.4x

100

40

×x=0.4x

Also,

In the past, 70% of successful cell phones and 20% of unsuccessful cell phones received favorable reports.

So, Number of successfully launched+favorable cell phones is successful are:

40% of 70% of the total cell phones.

i.e.

P(A\bigcap B)=\dfrac{70}{100}\times \dfrac{40}{100}\times xP(A⋂B)=

100

70

×

100

40

×x

Hence, the probability P(A|B) is:

\begin{gathered}\dfrac{\dfrac{40}{100}\times \dfrac{70}{100}\times x}{\dfrac{40}{100}\times x}\\\\\\\\=\dfrac{70}{100}=0.70\end{gathered}

100

40

×x

100

40

×

100

70

×x

=

100

70

=0.70

[/tex]

Hence, the probability is:

0.70

‼️hope u satisfied with the answere ‼️