Question

A company is going to make frames as part of new product they are launching. The
rectangular frame will be cut out of a piece of steel and to keep the weight down the
final area should be 28 cm2. The inside of the frame has to be of dimension shown in the
Tigure. The inner rectangle length is 11 cm and breadth is 6 cm. width between them i
x cm.
a) Write an expression for area of the steel before cutting?
b) What will be the area after cutting?
c) Write the coefficient of x? of the expression formed in
part (a)​

Answer 1

a) An expression for area of the steel before cutting is 4x^2 + 34x + 66 .

b) The area after cutting is 4x^2 + 34x i.e, 28 cm^2.

c) The coefficient of x of the expression formed in part (a) is 34.

a) Write an expression for area of the steel before cutting?

Area of steel before cutting:

Area = (11 + 2x) × (6 + 2x)

Area = 66 + 22x + 12x + 4x^2

Area = 4x^2 + 34x + 66

b) What will be the area after cutting?

Area of steel after cutting out the 11 × 6 middle:

Area = 4x^2 + 34x + 66 - 66

Area = 4x^2 + 34x

As given the final area should be 28 cm^2.

c) Write the coefficient of x? of the expression formed in part (a)​

Area = 4x^2 + 34x + 66

The coefficient of x is 34.

Answer 2

Answer:

Step-by-step explanation: