Question

A company makes a mixture which contains 2% alcohol. if 10 litres of alcohol is added to the mixture, then the concentration increases to 5%. what is the approx. quantity of the mixture?

Answer 1

hello... ☺

quantity of alcohol=(2/100)*x=x/50 litres.

When 10 litres of alcohol is addedmixture
= (x+10) litres
Quantity of alcohol=10+ x/50 litres.

So % of alcohol in new mixture:-
= (10 + x/50)/(x+10) = 5/100

=>100(500+x) = 250(x+10)

=> 2(500+x) =5(x+10)

=> x= 950/3= 316.66 which is approximateky equal to... 316 litres......


thank you ☺

Answer 2

Answer:

A. 316

Explanation:

Let in the mixture of x liters, quantity of alcohol=(2/100)*x=x/50 liters.

When 10 liters of alcohol is added, quantity of mixture= (x+10) liters and  

Quantity of alcohol=10+ x/50 liters.

So % of alcohol in new mixture= (10 + x/50)/(x+10) = 5/100

=>100(500+x) = 250(x+10)

=> 2(500+x) =5(x+10)

=> x= 950/3= 316.66 ~ 316 liters.