Question

A company offered jobs to square root of half of all the students in a class and rejected the remaining. If the company rejected 90% of the students of the class how many students are there in class

Answer 1

Answer:

There are 50 students in the class.

Solution:

Let the total number of students in the class are P

By the given condition, the square root of half of the students were offered jobs, i.e., √(P/2) students were offered jobs.

Remaining students = P - √(P/2)

ATQ, P - √(P/2) = 90% of P

Then P - √(P/2) = 90/100 * P

or, P - √(P/2) = 9P/10

or, P - 9P/10 = √(P/2)

or, P/10 = √(P/2)

or, P² / 100 = P/2

or, P² / 50 = P

or, P² = 50P

or, P = 50 [ ∵ P ≠ 0 ]

Therefore, there are 50 students in the class.

Answer 2

Answer:

There are 50 students in the class out of which the company rejected 90% of the students, and offered jobs to the rest of the students.

Step-by-step explanation:

Let the total number of students be x.

According to the question, the company offered jobs to square root of half of all the students in the class.

Thus, the company offered jobs to $\sqrt{\frac{x}{2} }$ students.

Again, in the question, it is mentioned that 90% of the students in the class were rejected by the company, which implies that only 10% of the students got the jobs.

∴ we have, 10% of x = $\sqrt{\frac{x}{2}}$

⇒ $\frac{10}{100} * x = \sqrt{\frac{x}{2} }$

⇒ $\frac{x}{10} = \sqrt{\frac{x}{2} }$

Squaring both sides, we get,

$\frac{x^{2} }{100} = \frac{x}{2}$

⇒ $\frac{x^{2} }{x} = \frac{100}{2}$

⇒ x = 50.

Thus, the total number of students present in the class is 50.