Question

A company packages its milk powder in cylindrical<br />container whose base has a diameter of 14 cm and height<br />20 cm. Company places a label around the surface of the container. If the label is placed 2 cm from top and bottom, what is the area of the label.​

Answer 1

Answer:

Heya Mate ✌️

CSA of cylinder =2\pi rh=2πrh

Height of label=20-2-2=16=20−2−2=16

Radius =7=7cm

CSA of label=2\times \dfrac{22}{7}\times 7\times 16=2×

7

22

×7×16

=704cm^2=704cm^2

hope it will be helpful ✌️

Answer 2

$\Huge{\boxed{\mathcal{\black{yo}}}}$

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CSA of cylinder =2\pi rh=2πrh

CSA of cylinder =2\pi rh=2πrhHeight of label=20-2-2=16=20−2−2=16

CSA of cylinder =2\pi rh=2πrhHeight of label=20-2-2=16=20−2−2=16Radius =7=7cm

CSA of cylinder =2\pi rh=2πrhHeight of label=20-2-2=16=20−2−2=16Radius =7=7cmCSA of label=2\times \dfrac{22}{7}\times 7\times 16=2×

CSA of cylinder =2\pi rh=2πrhHeight of label=20-2-2=16=20−2−2=16Radius =7=7cmCSA of label=2\times \dfrac{22}{7}\times 7\times 16=2× 7

CSA of cylinder =2\pi rh=2πrhHeight of label=20-2-2=16=20−2−2=16Radius =7=7cmCSA of label=2\times \dfrac{22}{7}\times 7\times 16=2× 722

CSA of cylinder =2\pi rh=2πrhHeight of label=20-2-2=16=20−2−2=16Radius =7=7cmCSA of label=2\times \dfrac{22}{7}\times 7\times 16=2× 722

CSA of cylinder =2\pi rh=2πrhHeight of label=20-2-2=16=20−2−2=16Radius =7=7cmCSA of label=2\times \dfrac{22}{7}\times 7\times 16=2× 722 ×7×16

CSA of cylinder =2\pi rh=2πrhHeight of label=20-2-2=16=20−2−2=16Radius =7=7cmCSA of label=2\times \dfrac{22}{7}\times 7\times 16=2× 722 ×7×16=704cm^2=704cm^2

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