Math, asked by yannmatheo78, 4 months ago

A company rents out 17 food booths and 25 game booths at the county fair. The fee for a food booth is $200 plus $9 per day. The fee for a game booth is $80 plus $4 per day. The fair lasts for d days, and all the booths are rented for the entire time. Enter a simplified expression for the amount, in dollars, that the company is paid.

Answers

Answered by fayaaz1805
1

Answer:

Step-by-step explanation:

Food both,

The initial amount paid = $200 = a

Amount increased for each day = $9 = d

No.of days the fair lasts = d = n

No.of booths =17

A= 17a = 17 ×200 = $3400

Sum of amount paid to the company(food booth) = Sₙ

Sₙ₁= n/2 [2A +(n-1)d]

   = d/2 [2(3400) + (d-1) 9]

   = d/2 [6800 +9d-9]

   = d/2 [6791 +9d]

   = 6791d/2 +9d²/2

Game booth,

a=$60 , d=$4 , n=d, A= 25(80) = $2000

Sₙ₂ = d/2 [2(2000) + (d-1) 4]

     = d/2 [4000 +4d-4

     = d/2 [ 3996 +4d]

     = 3996d/2 + 4d²/2

Total cost to be paid = Sₙ₁ +Sₙ₂

                                   = 6791d/2 +9d²/2 + 3996d/2 + 4d²/2

                                   = [6791d + 3996d + 9d²+ 4d²] / 2

                                   = [10,787d + 13d²]/2

Answered by jasprit155
0

=[6719d + 3996d+ 9d²+4d²]/2

= [10,787d+13d²] /2

is the right answer

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