Question

A company that has been assigned the task of building 50 offices in Delhi needs to
shortlist suppliers for the building process. 10 suppliers sent their proposals. The
company decided to select 4 of the proposals simultaneously. How many groups of 4
proposals could be selected by the company?​

Answer 1

Answer:

10c4/4! this is the correct answer

Answer 2

Concept:

In mathematics, a combination is a selection of items from a set that has distinct members, such that the order of selection does not matter.

For  example:  Picking a team of 3 people from a group of 10.

Given:

We are given that there are 10 suppliers who has sent the proposal to the company.

Also, the company decided to select 4 of the proposals simultaneously.

Find:

We need to find the number of groups of 4 proposals that could be selected by the company.

Solution:

We will be using combinations for it as the order of selection does not matter.

Formula for combination:

$^{n} C_{r} =\frac{n!}{r!(n-r)!}$

We have:

n=10 and r=4

Substituting the values in the formula:

¹⁰C₄ = (10!) / (4!)(6!)

¹⁰C₄ = 210

Therefore, the number of groups of 4 proposals that could be selected by the company are 210.

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