A company tracks their profits with respect to number of years (t)(t) from the year of establishment. At the end of the second year (i.e. t=2t=2) the company registers neither profit nor loss. The same situation arises at the end of fifth and seventh year. If the equation relating the profit (in thousands) and the number of years tt, is a cubic polynomial in tt, with leading coefficient being 20. What will be the profit (in thousands) at the end of 10 years?
Answers
Given : A company tracks their profits with respect to number of years (t) from the year of establishment.
At the end of the second year (i.e. t=2 ) the company registers neither profit nor loss.
The same situation arises at the end of fifth and seventh year. T
The equation relating the profit (in thousands) and the number of years t , is a cubic polynomial in t , with leading coefficient being 20.
To Find : Profit (in thousands) at the end of 10 years
Solution:
At t = 2 profit = 0
at t = 5 profit = 0
at t = 7 profit = 0
P(t) = k(t - 2)(t - 5)(t - 7) as it cubic polynomial
P(t) = profit (in thousands) at the end of t years
as leading coefficient is zero hence k = 20
=> P(t) = 20(t - 2)(t - 5)(t - 7)
profit (in thousands) at the end of 10 years
t = 10
=> P(10) = 20(10 - 2)(10 - 5)(10 - 7)
= 20(8)(5)(3)
= 2400
profit (in thousands) at the end of 10 years = 2400
Learn More:
Find a quadratic polynomial whose zeroes are 1/2 , 4 - Brainly.in
brainly.in/question/16158030
Find the quadratic polynomial whose zeroes are log 1000, log0.01*0.1
brainly.in/question/18047168
