(a) Compare the distance travelled in Section AB and BC.
(b) In the section car has zero acceleration and why?
(c) What is the magnitude of retardation between time 2t to 3t?
(d) Calculate total distance travelled in the time 0 to 3r
Answers
Answer:
As per the grapg,
Distance travelled in part BC= Area of rectangle tBC2t
=length×breadth
=(2t−t)×v
0
=v
0
t
Distance travelled in part AB= Area of rectangle ABt
=1/2×base×height
=1/2×t×v
0
=v
0
t/2
The distance travelled in part BC can be compared to the distance travelled in part AB, it is in the ratio, 2:1
(a)Uniformly velocity is shown at BC
(b) Uniformly acceleration is shown at AB
(c) Uniformly retardation is shown at CD
(a) The magnitude of acceleration is lower than that of retardation as the slope of line AB is less in comparison to the line CD
(b) Slope of line AB gives magnitude of acceleration while slope of line CD gives magnitude of retardation
Slope of line AB=v
0
/t
Slope of line CD=v
0
/0.5t
The magnitude of acceleration and retardation =Slope of line AB/Slope of line CD
=(v
0
/t)/(v
0
/0.5t)=1:2