Physics, asked by Abaan2972, 1 year ago

A compass needle placed at a distance r from a short magnet in Tan A position shows a deflection of 60°. If the distance is increased to r(3)^{1/3}, then deflection of compass needle is(a) 30°(b) 60\times (3)^{\frac{1}{3}}(c) 60\times (3)^{\frac{2}{3}}(d) 60\times (3)^{\frac{3}{3}}

Answers

Answered by Anonymous
0

Hello Friend

The answer of u r question is

Option.D

Thank you

Answered by kingArsh07
0

HERE IS YOUR ANSWER :-

Option No. D

Thanx❤❤❤

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