Question

A compaund (A) has molecular formula of C6H13Br.
When it is treated with Mg metal in the ether,
a Grignaid reagent is formed which on hydrolysis with
dilute acid produces the compound n-hexane as a product
when compaund A is reacted with sodium metal in ethers
the product is obtained is 4,5-diethyloctane. From the above
information deduce the structural formula of (A). Give equation
for the reaction involved ?
Ans )​

Answer 1

Explanation:

To Do -

1. Structural formula of Compound A
2. Equation for the reaction involved

When Magnesium reacts with Haloalkane in the presence of dry ether then it form alkylmagnesium halide.

Reaction:

C₆H₁₃Br + Mg → C₆H₁₃MgBr (in the presence of dry ether)

When Alkylmagnesium halide reacts with water then it forms alkane and Magnesium hydroxy halide

Reaction:

C₆H₁₃MgBr + H₂O → C₆H₁₄ (n-hexane) + MgBr(OH) (in acidic medium)

When Haloalkane reacts with sodium in the presence of dry ether then it forms alkane.

Reaction:

C₆H₁₃Br + Na →

C₂H₅ C₂H₅

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H₃C–H₂C-H₂C–H₂C–H₂C–H₂C–H₂C–CH₃

(in the presence of dry ether)

Therefore,

Structural formula of Compound A is

H

|

H₃C–H₂C–H₂C–H₂C–H₂C–C–Br

|

H