Math, asked by Dheerajkhemani5979, 1 year ago

A complete 75% of a work in 45 days and b is 25% moire efficient than a. A and b working togtether will complete whole work in how many days?

Answers

Answered by amitnrw
1

Answer:

26.67 Days

Step-by-step explanation:

Let say work = 1

75 % of work = (75/100) * 1 = 3/4

3/4 is done by A in 45 day

1 is done by A in = 45/(3/4) = 60 Days

Work done by A in 1 Day = 1/60

B is 25 % More efficient than A

so work done by B in 1 day = Work done by A + (25/100)*(workdone by A)

= 1/60  + (25/100)(1/60)

= 1/60 + 1/240

= (4 + 1)/240

= 5/240

= 1/48

A + B 's 1 day work =  1/60 + 1/48

= (4 + 5 )/240

= 9/240

A& B will complete the work in 240/9 days

= 26.67 Days

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