Math, asked by abunasarghazi235, 10 months ago

a complete cylinderical drill of radius 6cm is made in a solid cylinder with base radius 8cm and height 10cm.Find total surface area of this hollow cylinder.​

Answers

Answered by vy19161916
1

Answer:1056 cm²

Step-by-step explanation:

Outer radius of Cylinder  = 8 cm

Inner radius of cylinder Ri = 6 cm (after drilling)

Height of the cylinder H = 10 cm

Find - Total surface area of the hollow cylinder.

There are total 4 surfaces in given cylinder.

Outer surface area = 2π * Outer radius * height  

=  2π * 8 * 10 cm²

= 160π cm²

inner surface area = 2π * inner radius * height  

=  2π * 6 * 10 cm²

= 120π cm²

Bottom surface + top surface = 2 * π (Outer radius² - Inner Radius²)

= 2π(8² - 6²)

= 56π cm²

Total surface Area = 160π + 120π + 56π cm²

= 336π cm²

π = 22/7

= 336 (22/7)

= 48 * 22

= 1056 cm²

Total surface area of this hollow cylinder will be 1056 cm

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Answered by Anonymous
0

Answer: 1056cm²

Step-by-step explanation:

Outer radius of Cylinder  = 8 cm

Inner radius of cylinder Ri = 6 cm (after drilling)

Height of the cylinder H = 10 cm

Find - Total surface area of the hollow cylinder.

There are total 4 surfaces in given cylinder.

Outer surface area = 2π * Outer radius * height  

=  2π * 8 * 10 cm²

= 160π cm²

inner surface area = 2π * inner radius * height  

=  2π * 6 * 10 cm²

= 120π cm²

Bottom surface + top surface = 2 * π (Outer radius² - Inner Radius²)

= 2π(8² - 6²)

= 56π cm²

Total surface Area = 160π + 120π + 56π cm²

= 336π cm²

π = 22/7

= 336 (22/7)

= 48 * 22

= 1056 cm²

Total surface area of this hollow cylinder will be 1056 cm

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