a complete cylinderical drill of radius 6cm is made in a solid cylinder with base radius 8cm and height 10cm.Find total surface area of this hollow cylinder.
Answers
Answer:1056 cm²
Step-by-step explanation:
Outer radius of Cylinder = 8 cm
Inner radius of cylinder Ri = 6 cm (after drilling)
Height of the cylinder H = 10 cm
Find - Total surface area of the hollow cylinder.
There are total 4 surfaces in given cylinder.
Outer surface area = 2π * Outer radius * height
= 2π * 8 * 10 cm²
= 160π cm²
inner surface area = 2π * inner radius * height
= 2π * 6 * 10 cm²
= 120π cm²
Bottom surface + top surface = 2 * π (Outer radius² - Inner Radius²)
= 2π(8² - 6²)
= 56π cm²
Total surface Area = 160π + 120π + 56π cm²
= 336π cm²
π = 22/7
= 336 (22/7)
= 48 * 22
= 1056 cm²
Total surface area of this hollow cylinder will be 1056 cm
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Answer: 1056cm²
Step-by-step explanation:
Outer radius of Cylinder = 8 cm
Inner radius of cylinder Ri = 6 cm (after drilling)
Height of the cylinder H = 10 cm
Find - Total surface area of the hollow cylinder.
There are total 4 surfaces in given cylinder.
Outer surface area = 2π * Outer radius * height
= 2π * 8 * 10 cm²
= 160π cm²
inner surface area = 2π * inner radius * height
= 2π * 6 * 10 cm²
= 120π cm²
Bottom surface + top surface = 2 * π (Outer radius² - Inner Radius²)
= 2π(8² - 6²)
= 56π cm²
Total surface Area = 160π + 120π + 56π cm²
= 336π cm²
π = 22/7
= 336 (22/7)
= 48 * 22
= 1056 cm²
Total surface area of this hollow cylinder will be 1056 cm