Question

(a)
Complete the following ray diagram :
- 15 cm
30 cm
(b)
(c)
Find the nature, position and size of the image formed.
Use mirror formula to determine the magnification in this case.​

Answer 1

Answer:

b) f = -30cm

u = -15cm

v = ?cm

1/f = 1/u + 1/v

1/-30 = 1/-15 + 1/v

1/v = 1/-30 - 1/-15

1/v = 1/30

v = 30cm

m=-v/u

m = -30/-15

m = +2

m=h¹/h²

2 = h¹/h²

h¹ = 2h²

The image formed is virtual and erect

Explanation

Answer 2

Answer:f = -30cm

u = -15cm

v = ?cm

1/f = 1/u + 1/v

1/-30 = 1/-15 + 1/v

1/v = 1/-30 - 1/-15

1/v = 1/30

v = 30cm

m=-v/u

m = -30/-15

m = +2

m=h¹/h²

2 = h¹/h²

h¹ = 2h²

The image formed is virtual and erect

Explanation: