A completes 80% of work in 20 days. A and B together finish the remaining 20% of work in 3 days. How long would it take B alone to do the work?
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A completes 80% of a work in 20 days. Then B also joins and A and B together finish the remaining work in 3 days. How long does it need for B if he alone completes the work? Work done by A and B in 3 days = 20/100 = 1/5 (Because remaining 20% is done in 3 days by A and B)
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Answer:
B can complete the work in 75/2 days = 37 ½ days
Step-by-step explanation:
Work done by A in 20 days = 80/100 = 8/10 = 4/5
Work done by A in 1 day = (4/5) / 20 = 4/100 = 1/25 --- (1)
Work done by A and B in 3 days = 20/100 = 1/5 (Because remaining 20% is done in 3 days by A and B)
Work done by A and B in 1 day = 1/15 ---(2)
Work done by B in 1 day = 1/15 - 1/25 = 2/75
=> B can complete the work in 75/2 days = 37 ½ days
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