Math, asked by yudhnegi98, 1 year ago

'A' completes a piece of work in 12 days. 'B' is 20% more efficient than 'A'. 'C
completes the same work taking 6 more days than 'B'. What will be the time
(days) taken by 'B' & 'C'jointly to complete the work​

Answers

Answered by amitnrw
6

Answer:

80/13  Days

Step-by-step explanation:

A' completes a piece of work in 12 days

=> A's 1 Day Work = 1/12

B' is 20% more efficient than 'A

=> B's 1 day work = (1/12) + (20/100)(1/12)

= (1/12)(1.2)

= 1/10

=> B Complete the work in 10 Days

C completes the same work taking 6 more days than 'B

=> C completes work in 10 + 6 = 16 Days

=> C's 1 day work = 1/16

B & C together 1 Day work = 1/10 + 1/16

= (8 + 5)/80

= 13/80

'B' & 'C' jointly complete the work​ in  = 80/13  Days

Answered by Anonymous
2

Answer:

Step-by-step explanation:

Step-by-step explanation:

A' completes a piece of work in 12 days

=> A's 1 Day Work = 1/12

B' is 20% more efficient than 'A

=> B's 1 day work = (1/12) + (20/100)(1/12)

= (1/12)(1.2)

= 1/10

=> B Complete the work in 10 Days

C completes the same work taking 6 more days than 'B

=> C completes work in 10 + 6 = 16 Days

=> C's 1 day work = 1/16

B & C together 1 Day work = 1/10 + 1/16

= (8 + 5)/80

= 13/80

'B' & 'C' jointly complete the work​ in = 80/13 Days

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