'A' completes a piece of work in 12 days. 'B' is 20% more efficient than 'A'. 'C
completes the same work taking 6 more days than 'B'. What will be the time
(days) taken by 'B' & 'C'jointly to complete the work
Answers
Answer:
80/13 Days
Step-by-step explanation:
A' completes a piece of work in 12 days
=> A's 1 Day Work = 1/12
B' is 20% more efficient than 'A
=> B's 1 day work = (1/12) + (20/100)(1/12)
= (1/12)(1.2)
= 1/10
=> B Complete the work in 10 Days
C completes the same work taking 6 more days than 'B
=> C completes work in 10 + 6 = 16 Days
=> C's 1 day work = 1/16
B & C together 1 Day work = 1/10 + 1/16
= (8 + 5)/80
= 13/80
'B' & 'C' jointly complete the work in = 80/13 Days
Answer:
Step-by-step explanation:
Step-by-step explanation:
A' completes a piece of work in 12 days
=> A's 1 Day Work = 1/12
B' is 20% more efficient than 'A
=> B's 1 day work = (1/12) + (20/100)(1/12)
= (1/12)(1.2)
= 1/10
=> B Complete the work in 10 Days
C completes the same work taking 6 more days than 'B
=> C completes work in 10 + 6 = 16 Days
=> C's 1 day work = 1/16
B & C together 1 Day work = 1/10 + 1/16
= (8 + 5)/80
= 13/80
'B' & 'C' jointly complete the work in = 80/13 Days