A complex is represented as CoCl3.xNH3. Its 0.1 m solution in aqueous solution shows
AT: = 0.558°C, KF(H2O) = 1.86 mol K and assume 100% ionization and co-ordination
number of Co(III) is six. What is the complex?
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Answer:
complex is represented as CoCl
3
.xNH
3
. It's 0.1 molal solution in aq. solution showsΔT
f
=0.558
∘
C.K
f
forH
2
O is 1.86Kmol
−1
kg. Assuming 100 per ionisation of complex and coordination no. of Co is six , then the formula of complex is [CO(NH
3
)
5
Cl]Cl
2
.
State whether the statement is True or False
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Molarity of Solution = Cm = 0.1
Depression in freezing point = ∆T = 0.558℃
K(H2O) = 1.86 kg/mol/K
As we know that, ∆T = K×i×m
0.558 = 1.86 × 0.1 × i
Therefore, i = 0.558/0.186 = 3
or, i ≈ 3 indicates that complex ionize to form three ions since coordination number is 6 hence x = 6.
That is, CoCl3.5NH3 --» [Co(NH3)5Cl]Cl2
So, the complex is [Co(NH3)5Cl]Cl2