Question

A complex number, (a + bi), multiplied by (2 + 3i) and added to -i gives the product of (-11 + 5i) and (1 – i).

Answer 1

Step-by-step explanation:

(a + bi)(2 + 3i) - i = (-11 + 5i)(1 - i)

(a + bi)(2 + 3i) - i = -11 + 11i + 5i - 5i²

(a + bi)(2 + 3i) - i = -6 + 16i

(a + bi)(2 + 3i) = -6 + 17i

a+bi={-6+17i}{2+3i}

a+bi={(-6+17i)(2-3i)}{(2+3i)(2-3i)}

a+bi={-12+18i+34i-51i^2}{4+9}

a+bi={39+52i}{13}

a + bi = 3 + 4i

a = 3, b = 4

Hope it is helpful.......

Answer 2

(2a-3b) + i(3a +2b) -i =6 -6i

= 6 - 5i

Step-by-step explanation:

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