Question

a complex of iron contain 45.6% iron mass calculate number of iron atom present in 15 .0g of this complex​

Answer 1

Answer:

5 g * 0.456 * 1mole Fe/55.8g Fe * 6.02 E23 = 0.2456 E23 = 2.46 E22

Answer 2

Explanation:

Given percentage by mass of Fe in the compound = 45.6% That means 100g of the substance contains 45.6g of Fe, So 5g of the substance will contain x grams of Fe. => X = (45.6 X 5)/100 = 2.28g Now no. of atoms = Moles x Avogadro No. => No. of atoms = (Given Mass of Fe/ Molar Mass of Fe) x 6.02 x 10"23 = (2.28/56) X 6.02 X 10"23 = 2.450 x 10"22 atoms of Fe

here is your answe

if you liked the answer add me to the brainlist