A compliment \B compliment = B-A
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Answer:
How can I prove that (A-B) = B'-A' in a set?
First, i’ll mention here, how do the following 2 Set Operations, differ from each other. ‘Complement' & ‘Difference'
For finding the ‘ Complement' of two sets, one set should be super set, & the other should be its sub set. Then we select the elements , which are present in super set but not in sub set. This forms the complement of the sub set.
But there is no such restriction while finding the ‘ Difference' of two sets. We may find the difference of any 2 sets X & Y, one may be subset or may not be subset. X-Y = the set of elements, which are present in X but not in Y.
Now, To Prove: ( A - B) =
A−B implies complement of B relative to A.
i.e, if x∈A−B
=>x∈A and x∉B
=>x∉A′ and x∈B′
=>x∈B′−A′
=>A−B⊆B′−A′—————(1)
Let x∈B′−A′
=>x∈B′ and x∉A′
=>x∉B and x∈A
=>x∈A−B
=>B′−A′⊆A−B—————−(2)
From (1) and (2) we have,
B′−A′=A−B