Question

A composite rod is 1000mm long. it's two ends are 40mm2 and 30mm2 in area and length are 400mm and 600mm respectively.lf the rod is subjected to an axial tensile load of 1000n,what will be its total elongation (E=200Gp)?
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Answer 1

k=LEA

k1=L1EA1,k2=L2EA2,k3=L3EA3

k1=E×30040×10−3

k2=E×20030×10−3

k3=E×50020×10−3

k1=34E×10−4

k1=33E×10