Question

A composite slab consists of two slabs a and b of different materials but of the same thickness placed of a and b are k1 and k2 respectively. A steady temperature difference of 12c is maintained across the composite slab. If k1 = k2/2, the temperature difference across slab a will be (a) 4c (b) 8c (c) 12c (d) 16c

Answer 1

The temperature difference across slab a will be 8°C

Explanation:

Temperature at Slab A is lower.

Let temperature at junction be To  .

Given:

TB -TA = 12

k2 = 2k1

Then, k1  To - TA / RA  = k2  TB - To / RB  

k1 (To - TA) =  k2( TB - To)

To−T  A =8 °  C

Thus the temperature difference across slab a will be 8°C.

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