Science, asked by MANOJPRADHANI4709, 19 days ago

A composite wall is made of two layers of 0.3 m and 0.15 m thickness with surfaces held at 600ºC and 20ºC respectively. If the conductivities are 20 and 50 W/mK, determine the heat conducted. In order to restrict the heat loss to kW/m2
another layer of 0.15m thickness is proposed. Determine the thermal conductivity 5 kW/m2
of the material required.

Answers

Answered by skdruv760
0

Answer:

2.7

A composite wall is made of two layers of 0.3 m and 0.15 m thickness with surfaces held at 600°C

and 20°C respectively. If the conductivities are 20 and 50 W/mK, determine the heat conducted.

In order to restrict the heat loss to 5 kW/m2 another layer of 0.15 m thickness is proposed.

Determine the thermal conductivity of the material required (32.22 kW, 1.53 W/mK).

Explanation:

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