A composite wire is prepared by joining
a tungsten wire and steel wire end to end.
Both the wires are of the same length
and the same area of cross section. If
this composite wire is suspended to a
rigid support and a force is applied to
its free end, it gets extended by 3.25mm.
Calculate the increase in length of
tungsten wire and steel wire separately.
Answers
object having mass 25 kg has more inertia because when mass is more inertia will be more .
Δl
s
=2.393 mm is the increment in the length of steel wire.
\Delta l_t=0.857\ mmΔl
t
=0.857 mm s the increment in the length of tungsten wire.
Explanation:
Since the wires are connected end to end i.e. in series so the force acting on them will be equal.
According to given, the length and cross-sectional area of both the tungsten wire and the steel wire are equal.
\Delta l_s+\Delta l_t=3.25\ mmΔl
s
+Δl
t
=3.25 mm ====>>> 1)
We have,
Young's modulus of steel, E_s=215000\ MPaE
s
=215000 MPa
Young's modulus of tungsten, E_t=600000\ MPaE
t
=600000 MPa
So accordingly the stress in both the wires will be equal:
\sigma_s=\sigma_tσ
s
=σ t
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