Question

A compound A (C₂H₄O₂) reacts with Na metal to form a compound ‘B’ and evolves a gas which burns with a pop sound. Compound ‘A’ on treatment with an alcohol ‘C’ in presence of an acid forms a Sweet smelling compound ‘D’ (C₄H₈O₂). On addition of NaOH to ‘D’ gives back B and C. Identify A, B, C and D write the reactions involved.

Answer 1

            C — Ethanoic acid.

R — Sodium salt of ethanoic acid (sodium acetate) and gas evolved is hydrogen.

A — Methanol.

S — Ester (Methyl acetete).

Answer 2

The first reaction:

2CH3COOH + 2Na -----> 2CH3COONa + H2 (Gas)

CH3COONa -- Sodium Ethanoate

The second reaction:

CH3COOH + C2H5OH -----> CH3COOC2H5 + H2O

Here in this reaction

CH3COOH – Acetic Acid

C2H5OH – Ethanol

CH3COOC2H5 – Ester

The third reaction :

CH3COOC2H5 + NaOH -----> C2H5OH + CH3COONa

Your answers are

A – Acetic Acid

B – Sodium Ethanoate

C – Ethanol

D -- Ester

Read more in brainly:https://brainly.in/question/7004045