A compound 'C' (molecular formula C3H6O2) reacts with sodium metal to form 'R' and evolves a gas which burns with a pop sound. Compound 'C' on treatment with alcohol 'A' found in beer, in the presence of conc. sulphuric acid forms sweet smelling compound'S' (C5H10O2). On addition of NaOH to 'C' it also gives 'R' nad water. 'S' on treatment with NaOH gives back 'R' and 'A'.
Identify C,R,A and S and write down the reactions involved.
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Answer:
2 CH₃COOH + 2 Na ⇒ 2 CH₃COONa + H₂ ↑
( A ) ( B )
CH₃COOH + C₂H₅OH ⇒ CH₃COOC₂H₅ + H₂O
( C ) ( D )
CH₃COOC₂H₅ + NaOH ⇒ C₂H₅OH + CH₃COONa
Therefore we identified
A - CH₃COOH
B - CH₃COONa
C - C₂H₅OH
D - CH₃COOC₂H₅
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