Question

A compound c4h8 decolourizes a kmno4 solution structure of the compound

Answer 1

this is the structure hope it helps you

Answer 2

A compound $C4H8$ decolourizes a $KMnO4$ solution has four structures of the compound

Explanation:

• $C4H8$  is Baeyer's reagent which decolorizes alkaline KMnO4 solution
• It means the compound is an unsaturated compound having a double or triple bond
• double bond e quivalent =$C-H/2+N/2-X/2+1$
• $=4-8/2+0-0+1$
• $=1$
• This shows only double bond is present and no triple bond is present.
• CH2=CH-CH2-CH3 $But 1 -ene$
• CH2-CH=CH2-CH3 $But 2-ene$
• But 2 ene will have two forms cis but 2 ene and trans 2 ene.
• $2 Methyl prop 1 ene$ is the fourth structure
• So a total of four structures are found in molecular formula $C4H8$