Question

a compound contain 32.39%sodium 22.53%sulphur and rest oxygen derive emperical formula of compund​

Answer 1

Explanation:

First, convert percentages into grams.

32.39

%

=

32.39

g

22.53

%

=

22.53

g

45.07

%

=

45.07

g

Second, convert the grams into moles.

32.39 g

22.99 g/mol Na

=

1.409 mol Na

22.53 g

32.06 g/mol S

=

0.7027 mol S

45.07 g

16.00 g/mol O

=

2.817 mol O

Third, convert the moles into a ratio of atoms.

2.817 mol O

0.7027 mol S

=

4.009 O

1 S

1.409 mol Na

0.7027 mol S

=

2.005 Na

1 S

Rounding to integers, the ratio is 1 S: 2 Na : 4 O

N

a

2

S

O

4