Question

A compound contain 54.54% carbon, 9.09
Hydrogen
and 36.36% oxygens. Its molar
Mass is 88. What are its emperical
and Molecular Formula?​

Answer 1

Answer:

Let amount of organic = 100 gm

amount of carbon = 54.55 g

amount of hydrogen = 9.09 g

Amount of oxygen = 36.26 g

number of mole of carbon =

12

34.55

=4.54583

number of mole of hydrogen =

1.018

9.09

=9

number of mole of oxygen =

16

36.26

=2.26

4.54833:9:2.26

2:4:1

organic compounds Empirical formula

=C

2

H

4

O

Molecular weight = 24+4+16=44

(for empirical)

Molecular weight = 2× vapour density

=2×44=88 g

To molecular formula be = C

4

H

8

O

Answer 2

Explanation:

ANSWER

Let amount of organic = 100 gm

amount of carbon = 54.55 g

amount of hydrogen = 9.09 g

Amount of oxygen = 36.26 g

number of mole of carbon =

12

34.55

=4.54583

number of mole of hydrogen =

1.018

9.09

=9

number of mole of oxygen =

16

36.26

=2.26

4.54833:9:2.26

2:4:1

organic compounds Empirical formula

=C

2

H

4

O

Molecular weight = 24+4+16=44

(for empirical)

Molecular weight = 2× vapour density

=2×44=88 g

To molecular formula be = C

4

H

8

O

2

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