Question

A compound containing 4.07%of hydrogen, 24.27% of carbon and 71.65%of chlorine.and its molecular weight is 98.96.
what is emperical formula and molecular formula...

Answer 1

❃Hey friend....❃
==============

☛Meet to your answer:-------

⚫No. of moles of Hydrogen (H) ======> 4.07/1
= 4 (approximately)

⚫No. of moles of Carbon (C)======> 24.27/12
= 2 (approximately)

⚫No. of moles of Chlorine (Cl)======> 71.65/35.5
= 2 (approximately)

⚫Then, the ratio would be :---
C : H : Cl
2 : 4 : 2
So, the
$empirical \: formula$
➡️CH$2$Cl

▪️Empirical formula mass = 12 + 2×1 + 35.5 = 49.5g
▪️Molecular formula mass (given) = 98.96g

⚫Now, for the value of "n" :---

n = molecular formula mass/empirical formula mass
➡️So, n = 2 (app.)

▪️Then, the Molecular formula would be = n × empirical formula
⚫So, 2 × CH2Cl

☞We got, C2H4Cl2 ------------$ans.$

✷Hope it will help you!!✷
Thanks!!☺️
==========