A compound containing 90% of carbon and 10 % of hydrogen empirical formula of the compound is
Answers
Answered by
50
Here is your answer.
Given C 90%, H10%.
So Moles of element C = 90/12 =7.5
So Moles of element H = 10/1 =10
Simplest molar ration of carbon= 7.5/7.5=1
Simplest molar ration of H= 10/7.5=1.33
whole no ratio element C= 1*3=3
whole no ratio element H= 1.33*3=4
so its C3H4
Hope it helps you.
Plzz mark me as brainliest..
Given C 90%, H10%.
So Moles of element C = 90/12 =7.5
So Moles of element H = 10/1 =10
Simplest molar ration of carbon= 7.5/7.5=1
Simplest molar ration of H= 10/7.5=1.33
whole no ratio element C= 1*3=3
whole no ratio element H= 1.33*3=4
so its C3H4
Hope it helps you.
Plzz mark me as brainliest..
Answered by
3
Answer:
C3H4
Explanation:
We have to calculate the empirical formulae-
Element Percent Mass Percent/Mass Ratio
C 90% 12 7.5 3
H 10% 1 10 4
Therefore we put the numbers and get the value- C3H4
GREAT! You did it!
Similar questions