A compound containing carbon, hydrogen and oxygen gave the following analytical data C=40.0% and=6.67%. Calculate the molecular formula of the compound if its molecular mass is 122.5
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For this we make a table as:
Element
%Composition
Atomic Mass
Mole Ratio
Simple Ratio
C
40.00%
12
(40/12)
(3.33/3.33)=1
H
6.67%
1
(6.67/1)
(6.667/3.33)=2
O
53.33%
16
(53.33/16)
(3.33/3.33)=1
∴ Formula of compound is =CH
2
O
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