Question

A compound containing carbon hydrogen and oxygen gavethe following analytical data:
C=40% H=6.67%
calculate molecular formula of a compound if its molecular mass is 180.

Answer 1

Glucose (C₆H₁₂O₆)

Step - by - step Explanation: It's given that total mixture weighs 180 grams.

→ 40% of C = 40/100 × 180 = 72g

→ 6.67% of H = 6.67/100 × 180 = 12g (approx)

→ 53.33 % of O = 53.33/100 × 180 = 96g (approx)

→ Moles of Carbon = 72/12= 6 moles

→ Moles of Hydrogen = 12/1 = 12 moles

→ Moles of Oxygen = 96/16 = 6 moles

→ Molar Ratio = 6:12:6 or 1:2:1

Compound is CH₂O or C₆H₁₂O₆ (Glucose)

Answer 2

Answer:

see the attachment ✌️❣️