Question

A compound contains 1.10 mol of K, 0.55 mol of Te, and 1.65 mol of O. What is the simplest formula of this compound?

Answer 1

Explanation:

If we assume you meant

0.55 mol tellurium , we get an

empirical formula of K2TeO3

.

Explanation:

We divide thru by the SMALLEST molar quantity, that of tellurium, to get an empirical formula.

Moles of tellurium

=0.55mol / 0.55mol= 1

Moles of potassium

=1.10 mol / 0.55 mol = 2

Moles of oxygen

=1.65 mol/ 0.55 mol= 3

And thus the empirical formula is

K2TeO3

.

All I have done is to divide thru by the SMALLEST MOLAR QUANTITY.