Question

a compound contains 13.13% hydrogen 52.14 % carbon and 34.73% oxygen its molar mass is 46.06 what are the empirical and molecular formula​

Answer 1

Answer:

Answer:H=13.13%O= 34.73%No. of moles of C= 52.14/12= 4.345No.of moles of H= 13.13/1= 13.13No.of moles of O= 34.73/16= 2.170Therefore,the ratio of the ...

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