a compound contains 2.68% magnesium how many atoms of magnesium are present in 15 gram of the compound
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Answer:
Explanation:
As it is given that percentage of magnesium in compound = 2.68 %
thus amount of magnesium in 15 g of compound = 2.68 % of 15 g
=2.68100×15
= 0.402 g Mg
As 24 g Mg contain = 6.022×1023 atom
Number of atoms in 0.402 g Mg = 6.022×102324×0.402 = 1.041 ×1022 atoms
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